What is the answer to log_{2}(x+3)=3-log_{2}(x+5) ?

The answer to log_{2}(x+3)=3-log_{2}(x+5) is x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x+3)=3-log_{2}(x+5)

lo g_{2} (x + 3) = 3 - lo g_{2} (x + 5)

x = - 1

Solution steps

lo g_{2} (x + 3) = 3 - lo g_{2} (x + 5)

Add

lo g_{2} (x + 5)

to both sides

lo g_{2} (x + 3) + lo g_{2} (x + 5) = 3 - lo g_{2} (x + 5) + lo g_{2} (x + 5)

Simplify

lo g_{2} (x + 3) + lo g_{2} (x + 5) = 3

Apply log rules

(x + 3) (x + 5) = 8

Solve

(x + 3) (x + 5) = 8 : x = - 1, x = - 7

x = - 1, x = - 7

Verify Solutions:

x = - 1

True

, x = - 7

False

The solution is

x = - 1

lo g_{4} (2 x + 4) - 3 = lo g_{4} (3)

lo g_{3} (2 x - 1) - lo g_{3} (x - 4) = 2

0.456 = ln (x^{2})

x, ln (y) = - ln (x) + c

0.6 = lo g_{10} (x)

What is the answer to log_{2}(x+3)=3-log_{2}(x+5) ?
The answer to log_{2}(x+3)=3-log_{2}(x+5) is x=-1
Solve for x: log_{2}(x+3)=3-log_{2}(x+5)
The solution is x=-1