What is the answer to solvefor x,ln(y)=-ln(x)+c ?

The answer to solvefor x,ln(y)=-ln(x)+c is x=(e^c)/y

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solvefor x,ln(y)=-ln(x)+c

solve for

x, ln (y) = - ln (x) + c

x = \frac{e ^{c}}{y}

Solution steps

ln (y) = - ln (x) + c

Move

ln (x)

to the left side

ln (y) + ln (x) = c

Move

ln (y)

to the right side

ln (x) = c - ln (y)

Apply log rules

x = \frac{e ^{c}}{y}

0.6 = lo g_{10} (x)

lo g_{10} (x^{2}) = 2

ln (27) - ln (x) = ln (x - 6)

lo g_{3} (x + 4) + lo g_{3} (x - 4) = 2

ln (x + e) - ln (x) = 1

What is the answer to solvefor x,ln(y)=-ln(x)+c ?
The answer to solvefor x,ln(y)=-ln(x)+c is x=(e^c)/y