What is the answer to log_{3}(x+4)+log_{3}(x-4)=2 ?

The answer to log_{3}(x+4)+log_{3}(x-4)=2 is x=5

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log_{3}(x+4)+log_{3}(x-4)=2

lo g_{3} (x + 4) + lo g_{3} (x - 4) = 2

x = 5

Solution steps

lo g_{3} (x + 4) + lo g_{3} (x - 4) = 2

Apply log rules

(x + 4) (x - 4) = 9

Solve

(x + 4) (x - 4) = 9 : x = 5, x = - 5

x = 5, x = - 5

Verify Solutions:

x = 5

True

, x = - 5

False

The solution is

x = 5

ln (x + e) - ln (x) = 1

lo g_{3} (81) - lo g_{3} (x - 4) = 2

ln (3 x - 12) = 4

lo g_{2} (6 - x) - lo g_{2} (4 - x) = 2

lo g_{5} (x - 4) = 1 - lo g_{5} (x - 8)

What is the answer to log_{3}(x+4)+log_{3}(x-4)=2 ?
The answer to log_{3}(x+4)+log_{3}(x-4)=2 is x=5
Solve for x: log_{3}(x+4)+log_{3}(x-4)=2
The solution is x=5