What is the answer to log_{8}(x+6)=1-log_{8}(x+4) ?

The answer to log_{8}(x+6)=1-log_{8}(x+4) is x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{8}(x+6)=1-log_{8}(x+4)

lo g_{8} (x + 6) = 1 - lo g_{8} (x + 4)

x = - 2

Solution steps

lo g_{8} (x + 6) = 1 - lo g_{8} (x + 4)

Add

lo g_{8} (x + 4)

to both sides

lo g_{8} (x + 6) + lo g_{8} (x + 4) = 1 - lo g_{8} (x + 4) + lo g_{8} (x + 4)

Simplify

lo g_{8} (x + 6) + lo g_{8} (x + 4) = 1

Apply log rules

(x + 6) (x + 4) = 8

Solve

(x + 6) (x + 4) = 8 : x = - 2, x = - 8

x = - 2, x = - 8

Verify Solutions:

x = - 2

True

, x = - 8

False

The solution is

x = - 2

lo g_{3} (4 x - 1) = 3

lo g_{5} (9 - x) = 2

lo g_{2} (x + 5) = 3 - lo g_{2} (x + 3)

lo g_{5} (x) + lo g_{5} (30) = 3

ln (x) + ln (x + 3) = 4

What is the answer to log_{8}(x+6)=1-log_{8}(x+4) ?
The answer to log_{8}(x+6)=1-log_{8}(x+4) is x=-2
Solve for x: log_{8}(x+6)=1-log_{8}(x+4)
The solution is x=-2