What is the answer to ln(x)+ln(x+3)=4 ?

The answer to ln(x)+ln(x+3)=4 is x=(-3+sqrt(9+4e^4))/2

Solve for x: ln(x)+ln(x+3)=4

The solution is x=(-3+sqrt(9+4e^4))/2

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ln (x) + ln (x + 3) = 4

x = \frac{- 3 + 9 + 4 e ^{4}}{2}

Decimal Notation

x = 6.03977 \dots

Solution steps

ln (x) + ln (x + 3) = 4

Apply log rules

x (x + 3) = e^{4}

Solve

x (x + 3) = e^{4} : x = \frac{- 3 + 9 + 4 e ^{4}}{2}, x = \frac{- 3 - 9 + 4 e ^{4}}{2}

x = \frac{- 3 + 9 + 4 e ^{4}}{2}, x = \frac{- 3 - 9 + 4 e ^{4}}{2}

Verify Solutions:

x = \frac{- 3 + 9 + 4 e ^{4}}{2}

True

, x = \frac{- 3 - 9 + 4 e ^{4}}{2}

False

The solution is

x = \frac{- 3 + 9 + 4 e ^{4}}{2}

ln (x) + ln (x + 3) = 2 ln (x + 1)

- 5 + lo g_{2} (x + 8) = - 1

lo g_{x} (2) = \frac{1}{4}

e^{l n (1 - x)} = 2 x

3 ln (2 x) = 3 + ln (27)

What is the answer to ln(x)+ln(x+3)=4 ?
The answer to ln(x)+ln(x+3)=4 is x=(-3+sqrt(9+4e^4))/2
Solve for x: ln(x)+ln(x+3)=4
The solution is x=(-3+sqrt(9+4e^4))/2