What is the answer to 3ln(2x)=3+ln(27) ?

The answer to 3ln(2x)=3+ln(27) is x=(e^{(3+3ln(3))/3})/(2)

Solve for x: 3ln(2x)=3+ln(27)

The solution is x=(e^{(3+3ln(3))/3})/(2)

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3 ln (2 x) = 3 + ln (27)

x = \frac{e ^{\frac{3 + 3 l n ( 3 )}{3}}}{2}

Decimal Notation

x = 4.07742 \dots

Solution steps

3 ln (2 x) = 3 + ln (27)

Divide both sides by

3

ln (2 x) = \frac{3 + ln ( 27 )}{3}

Apply log rules

2 x = e^{\frac{3 + 3 l n ( 3 )}{3}}

Solve

2 x = e^{\frac{3 + 3 l n ( 3 )}{3}} : x = \frac{e ^{\frac{3 + 3 l n ( 3 )}{3}}}{2}

x = \frac{e ^{\frac{3 + 3 l n ( 3 )}{3}}}{2}

Verify Solutions:

x = \frac{e ^{\frac{3 + 3 l n ( 3 )}{3}}}{2}

True

The solution is

x = \frac{e ^{\frac{3 + 3 l n ( 3 )}{3}}}{2}

x ln (x + 2) = 0

ln (3) + ln (2 x) = 5

lo g_{5} (3 x + 1) = 2

2 lo g_{10} (x) = lo g_{10} (9)

lo g_{4} (x - 2) = 1 - lo g_{4} (x - 5)

What is the answer to 3ln(2x)=3+ln(27) ?
The answer to 3ln(2x)=3+ln(27) is x=(e^{(3+3ln(3))/3})/(2)
Solve for x: 3ln(2x)=3+ln(27)
The solution is x=(e^{(3+3ln(3))/3})/(2)