What is the answer to ln(3)+ln(2x)=5 ?

The answer to ln(3)+ln(2x)=5 is x=(e^5)/6

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ln(3)+ln(2x)=5

ln (3) + ln (2 x) = 5

x = \frac{e ^{5}}{6}

Decimal Notation

x = 24.73552 \dots

Solution steps

ln (3) + ln (2 x) = 5

Move

ln (3)

to the right side

ln (2 x) = 5 - ln (3)

Apply log rules

2 x = \frac{e ^{5}}{3}

Solve

2 x = \frac{e ^{5}}{3} : x = \frac{e ^{5}}{6}

x = \frac{e ^{5}}{6}

Verify Solutions:

x = \frac{e ^{5}}{6}

True

The solution is

x = \frac{e ^{5}}{6}

lo g_{5} (3 x + 1) = 2

2 lo g_{10} (x) = lo g_{10} (9)

lo g_{4} (x - 2) = 1 - lo g_{4} (x - 5)

lo g_{2} (x) = \frac{1}{2}

lo g_{4} (x - 3) + lo g_{4} (x + 3) = 2

What is the answer to ln(3)+ln(2x)=5 ?
The answer to ln(3)+ln(2x)=5 is x=(e^5)/6
Solve for x: ln(3)+ln(2x)=5
The solution is x=(e^5)/6