What is the answer to log_{4}(x-3)+log_{4}(x+3)=2 ?

The answer to log_{4}(x-3)+log_{4}(x+3)=2 is x=5

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log_{4}(x-3)+log_{4}(x+3)=2

lo g_{4} (x - 3) + lo g_{4} (x + 3) = 2

x = 5

Solution steps

lo g_{4} (x - 3) + lo g_{4} (x + 3) = 2

Apply log rules

(x - 3) (x + 3) = 16

Solve

(x - 3) (x + 3) = 16 : x = 5, x = - 5

x = 5, x = - 5

Verify Solutions:

x = 5

True

, x = - 5

False

The solution is

x = 5

- 2 lo g_{4} (x) = lo g_{4} (9)

ln (5 x) - ln (3 - 2 x) = 1

2 ln (x) + 1 = 0

lo g_{2} (x + 4) - lo g_{2} (x - 1) = 1

lo g_{3} (y) + 4 lo g_{y} (3) = 4

What is the answer to log_{4}(x-3)+log_{4}(x+3)=2 ?
The answer to log_{4}(x-3)+log_{4}(x+3)=2 is x=5
Solve for x: log_{4}(x-3)+log_{4}(x+3)=2
The solution is x=5