What is the answer to log_{2}(x+2)+log_{2}(x-5)=3 ?

The answer to log_{2}(x+2)+log_{2}(x-5)=3 is x=6

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log_{2}(x+2)+log_{2}(x-5)=3

lo g_{2} (x + 2) + lo g_{2} (x - 5) = 3

x = 6

Solution steps

lo g_{2} (x + 2) + lo g_{2} (x - 5) = 3

Apply log rules

(x + 2) (x - 5) = 8

Solve

(x + 2) (x - 5) = 8 : x = 6, x = - 3

x = 6, x = - 3

Verify Solutions:

x = 6

True

, x = - 3

False

The solution is

x = 6

lo g_{2} (x - 3) + lo g_{2} (x + 3) = 4

lo g_{3} (x - 6) + lo g_{3} (x) = 3

4.76 = - lo g_{10} (x)

lo g_{2} (x + 1) + lo g_{2} (x) = 1

ln (x^{2}) = 5

What is the answer to log_{2}(x+2)+log_{2}(x-5)=3 ?
The answer to log_{2}(x+2)+log_{2}(x-5)=3 is x=6
Solve for x: log_{2}(x+2)+log_{2}(x-5)=3
The solution is x=6