What is the answer to log_{2}(x+1)+log_{2}(x)=1 ?

The answer to log_{2}(x+1)+log_{2}(x)=1 is x=1

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log_{2}(x+1)+log_{2}(x)=1

lo g_{2} (x + 1) + lo g_{2} (x) = 1

x = 1

Solution steps

lo g_{2} (x + 1) + lo g_{2} (x) = 1

Apply log rules

(x + 1) x = 2

Solve

(x + 1) x = 2 : x = 1, x = - 2

x = 1, x = - 2

Verify Solutions:

x = 1

True

, x = - 2

False

The solution is

x = 1

ln (x^{2}) = 5

lo g_{5} (x + 1) = lo g_{5} (6)

lo g_{2 x - 1} (4.5 x) = 2

lo g_{4} (x + 1) = lo g_{2} (x - 1)

ln (ln (x)) = 5

What is the answer to log_{2}(x+1)+log_{2}(x)=1 ?
The answer to log_{2}(x+1)+log_{2}(x)=1 is x=1
Solve for x: log_{2}(x+1)+log_{2}(x)=1
The solution is x=1