What is the answer to log_{6}(x)+log_{6}(x-1)=1 ?

The answer to log_{6}(x)+log_{6}(x-1)=1 is x=3

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log_{6}(x)+log_{6}(x-1)=1

lo g_{6} (x) + lo g_{6} (x - 1) = 1

x = 3

Solution steps

lo g_{6} (x) + lo g_{6} (x - 1) = 1

Apply log rules

x (x - 1) = 6

Solve

x (x - 1) = 6 : x = 3, x = - 2

x = 3, x = - 2

Verify Solutions:

x = 3

True

, x = - 2

False

The solution is

x = 3

lo g_{x} (16) = \frac{2}{3}

lo g_{5} (2 x + 3) = lo g_{5} (3)

10 = - lo g_{10} (x)

lo g_{x} (25) = - 2

lo g_{3} (x) = 9 lo g_{x} (3)

What is the answer to log_{6}(x)+log_{6}(x-1)=1 ?
The answer to log_{6}(x)+log_{6}(x-1)=1 is x=3
Solve for x: log_{6}(x)+log_{6}(x-1)=1
The solution is x=3