What is the answer to 6+log_{3}(-4x)=9 ?

The answer to 6+log_{3}(-4x)=9 is x=-27/4

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6+log_{3}(-4x)=9

6 + lo g_{3} (- 4 x) = 9

x = - \frac{27}{4}

Decimal Notation

x = - 6.75

Solution steps

6 + lo g_{3} (- 4 x) = 9

Move

6

to the right side

lo g_{3} (- 4 x) = 3

Apply log rules

- 4 x = 27

Solve

- 4 x = 27 : x = - \frac{27}{4}

x = - \frac{27}{4}

Verify Solutions:

x = - \frac{27}{4}

True

The solution is

x = - \frac{27}{4}

lo g_{3} (x^{2} - 3 x - 1) = 0

lo g_{2} (x - 5) = 3 - lo g_{2} (x - 7)

ln (x) + ln (x - 1) = ln (6)

lo g_{16} (x) = (lo g_{4} (x))^{2}

lo g_{10} (x) = 7

What is the answer to 6+log_{3}(-4x)=9 ?
The answer to 6+log_{3}(-4x)=9 is x=-27/4
Solve for x: 6+log_{3}(-4x)=9
The solution is x=-27/4