What is the answer to log_{4}(10)+log_{4}(x+9)=4 ?

The answer to log_{4}(10)+log_{4}(x+9)=4 is x= 83/5

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log_{4}(10)+log_{4}(x+9)=4

lo g_{4} (10) + lo g_{4} (x + 9) = 4

x = \frac{83}{5}

Decimal Notation

x = 16.6

Solution steps

lo g_{4} (10) + lo g_{4} (x + 9) = 4

Move

lo g_{4} (10)

to the right side

lo g_{4} (x + 9) = 4 - lo g_{4} (10)

Apply log rules

x + 9 = \frac{128}{5}

Solve

x + 9 = \frac{128}{5} : x = \frac{83}{5}

x = \frac{83}{5}

Verify Solutions:

x = \frac{83}{5}

True

The solution is

x = \frac{83}{5}

0.56 = lo g_{10} (x)

ln (x) + ln (2 x) = 3

lo g_{7} (x + 6) - 1 = - lo g_{7} (x)

lo g_{64} (x) = \frac{1}{3}

lo g_{4} (x) = - 1

What is the answer to log_{4}(10)+log_{4}(x+9)=4 ?
The answer to log_{4}(10)+log_{4}(x+9)=4 is x= 83/5
Solve for x: log_{4}(10)+log_{4}(x+9)=4
The solution is x= 83/5