What is the answer to log_{4}(3x-7)=1 ?

The answer to log_{4}(3x-7)=1 is x= 11/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{4}(3x-7)=1

lo g_{4} (3 x - 7) = 1

x = \frac{11}{3}

Decimal Notation

x = 3.66666 \dots

Solution steps

lo g_{4} (3 x - 7) = 1

Apply log rules

3 x - 7 = 4

Solve

3 x - 7 = 4 : x = \frac{11}{3}

x = \frac{11}{3}

lo g_{2} (x) + lo g_{4} (x) = 9

lo g_{2} (y^{3}) = 6

lo g_{2} (x + 4) + lo g_{2} (x + 3) = 1

lo g_{a} (2) = \frac{1}{2}

lo g_{10} (x + 9) = 2 + lo g_{10} (x)

What is the answer to log_{4}(3x-7)=1 ?
The answer to log_{4}(3x-7)=1 is x= 11/3
Solve for x: log_{4}(3x-7)=1
The solution is x= 11/3