What is the answer to solvefor y,ln(y)=ln(x)+c ?

The answer to solvefor y,ln(y)=ln(x)+c is y=e^cx

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solvefor y,ln(y)=ln(x)+c

solve for

y, ln (y) = ln (x) + c

y = e^{c} x

Solution steps

ln (y) = ln (x) + c

Apply log rules

y = e^{c} x

lo g_{2} (x - 5) = 2 - lo g_{2} (x - 2)

lo g_{3} (x + 2) = 5

lo g_{10} (x) + lo g_{10} (4) = 0

lo g_{10} (x^{2}) = lo g_{3} (x)

x, ln (y) = ln (1 + x) + c

What is the answer to solvefor y,ln(y)=ln(x)+c ?
The answer to solvefor y,ln(y)=ln(x)+c is y=e^cx