What is the answer to log_{10}(x)+log_{10}(4)=0 ?

The answer to log_{10}(x)+log_{10}(4)=0 is x= 1/4

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log_{10}(x)+log_{10}(4)=0

lo g_{10} (x) + lo g_{10} (4) = 0

x = \frac{1}{4}

Decimal Notation

x = 0.25

Solution steps

lo g_{10} (x) + lo g_{10} (4) = 0

Move

lo g_{10} (4)

to the right side

lo g_{10} (x) = - lo g_{10} (4)

Apply log rules

x = \frac{1}{4}

Verify Solutions:

x = \frac{1}{4}

True

The solution is

x = \frac{1}{4}

lo g_{10} (x^{2}) = lo g_{3} (x)

x, ln (y) = ln (1 + x) + c

lo g_{2} (x^{2}) = 6

2 lo g_{4} (x - 1) + lo g_{4} (x - 1) = 6

lo g_{2} (x - 3) + lo g_{2} (x + 4) = 3

What is the answer to log_{10}(x)+log_{10}(4)=0 ?
The answer to log_{10}(x)+log_{10}(4)=0 is x= 1/4
Solve for x: log_{10}(x)+log_{10}(4)=0
The solution is x= 1/4