What is the answer to 4ln(4b)=ln(2b) ?

The answer to 4ln(4b)=ln(2b) is b= 1/(e^{\frac{7ln(2)){3}}}

Solve for b: 4ln(4b)=ln(2b)

The solution is b= 1/(e^{\frac{7ln(2)){3}}}

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4 ln (4 b) = ln (2 b)

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Solution steps

4 ln (4 b) = ln (2 b)

Apply log rules

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

Verify Solutions:

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

True

The solution is

b = \frac{1}{e ^{\frac{7 l n ( 2 )}{3}}}

ln (x) + ln (x - 6) = 1

2 lo g_{4} (x) - lo g_{4} (x + 5) = 2

x, ln (x) = 2

x, ln (x) = 0

lo g_{2} (x + 1) = 1 + 6 lo g_{x + 1} (2)

What is the answer to 4ln(4b)=ln(2b) ?
The answer to 4ln(4b)=ln(2b) is b= 1/(e^{\frac{7ln(2)){3}}}
Solve for b: 4ln(4b)=ln(2b)
The solution is b= 1/(e^{\frac{7ln(2)){3}}}