What is the answer to 2log_{2}(x)-log_{2}(2x)=3 ?

The answer to 2log_{2}(x)-log_{2}(2x)=3 is x=16

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2log_{2}(x)-log_{2}(2x)=3

2 lo g_{2} (x) - lo g_{2} (2 x) = 3

x = 16

Solution steps

2 lo g_{2} (x) - lo g_{2} (2 x) = 3

Apply log rules

x = 16

Verify Solutions:

x = 16

True

The solution is

x = 16

2 ln (x) = ln (3) + ln (6 - x)

lo g_{2} (x + 5) = 3 - lo g_{2} (x + 7)

lo g_{2} (x) + lo g_{2} (- 4 x + 12) = 3

lo g_{4} (4 x) - lo g_{4} (2 x - 4) = 3

lo g_{5} (x) = 1

What is the answer to 2log_{2}(x)-log_{2}(2x)=3 ?
The answer to 2log_{2}(x)-log_{2}(2x)=3 is x=16
Solve for x: 2log_{2}(x)-log_{2}(2x)=3
The solution is x=16