What is the answer to log_{3}(x+1)=log_{3}(x-1)+1 ?

The answer to log_{3}(x+1)=log_{3}(x-1)+1 is x=2

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log_{3}(x+1)=log_{3}(x-1)+1

lo g_{3} (x + 1) = lo g_{3} (x - 1) + 1

x = 2

Solution steps

lo g_{3} (x + 1) = lo g_{3} (x - 1) + 1

Apply log rules

x + 1 = (x - 1) \cdot 3

Solve

x + 1 = (x - 1) \cdot 3 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{2} (x + 1) = 4

ln (\frac{3}{t - 5}) = 1.92

ln (x - 2) = 0

lo g_{4} (2 x - 10) = \frac{1}{2}

lo g_{9} (x) + lo g_{3} (x) = 3

What is the answer to log_{3}(x+1)=log_{3}(x-1)+1 ?
The answer to log_{3}(x+1)=log_{3}(x-1)+1 is x=2
Solve for x: log_{3}(x+1)=log_{3}(x-1)+1
The solution is x=2