What is the answer to log_{2}(x+2)=2-log_{2}(x+5) ?

The answer to log_{2}(x+2)=2-log_{2}(x+5) is x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x+2)=2-log_{2}(x+5)

lo g_{2} (x + 2) = 2 - lo g_{2} (x + 5)

x = - 1

Solution steps

lo g_{2} (x + 2) = 2 - lo g_{2} (x + 5)

Add

lo g_{2} (x + 5)

to both sides

lo g_{2} (x + 2) + lo g_{2} (x + 5) = 2 - lo g_{2} (x + 5) + lo g_{2} (x + 5)

Simplify

lo g_{2} (x + 2) + lo g_{2} (x + 5) = 2

Apply log rules

(x + 2) (x + 5) = 4

Solve

(x + 2) (x + 5) = 4 : x = - 1, x = - 6

x = - 1, x = - 6

Verify Solutions:

x = - 1

True

, x = - 6

False

The solution is

x = - 1

lo g_{10} (x) - lo g_{10} (6) = 2

lo g_{2} (x + 5) = 2 - lo g_{2} (x + 2)

lo g_{6} (x + 8) + lo g_{6} (x - 8) = 2

lo g_{5} (- 3 x + 5) = 3

- 7 + lo g_{3} (x + 7) = - 4

What is the answer to log_{2}(x+2)=2-log_{2}(x+5) ?
The answer to log_{2}(x+2)=2-log_{2}(x+5) is x=-1
Solve for x: log_{2}(x+2)=2-log_{2}(x+5)
The solution is x=-1