What is the answer to ln(sqrt(x+1))-1=0 ?

The answer to ln(sqrt(x+1))-1=0 is x=e^2-1

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ln(sqrt(x+1))-1=0

ln (x + 1) - 1 = 0

x = e^{2} - 1

Decimal Notation

x = 6.38905 \dots

Solution steps

ln (x + 1) - 1 = 0

Move

1

to the right side

ln (x + 1) = 1

Apply log rules

x + 1 = e

Solve

x + 1 = e : x = e^{2} - 1

x = e^{2} - 1

Verify Solutions:

x = e^{2} - 1

True

The solution is

x = e^{2} - 1

lo g_{10} (x^{2}) = - 4

ln (2 x + 3) = 2 ln (3)

lo g_{x} (7) = - 2

5 = lo g_{b} (32)

lo g_{2} (x + 3) = - 1

What is the answer to ln(sqrt(x+1))-1=0 ?
The answer to ln(sqrt(x+1))-1=0 is x=e^2-1
Solve for x: ln(sqrt(x+1))-1=0
The solution is x=e^2-1