en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln(2^x)+ln(e^x)=3

Solution

ln (2^{x}) + ln (e^{x}) = 3

Solution

x = \frac{3}{ln ( 2 e )}

+1

Solution steps

ln (2^{x}) + ln (e^{x}) = 3

Apply log rules

2^{x} e^{x} = e^{3}

Solve

2^{x} e^{x} = e^{3} : x = \frac{3}{ln ( 2 e )}

x = \frac{3}{ln ( 2 e )}

Verify Solutions:

x = \frac{3}{ln ( 2 e )}

True

The solution is

x = \frac{3}{ln ( 2 e )}

Popular Examples

2log_{3}(x+1)=4

2 lo g_{3} (x + 1) = 4

2log_{10}(x-1)=log_{10}(x-1)

2 lo g_{10} (x - 1) = lo g_{10} (x - 1)

5log_{10}(x)=3+2log_{10}(x)

5 lo g_{10} (x) = 3 + 2 lo g_{10} (x)

0.567 = ln (x^{3})

log_{2}(x-1)+log_{2}(x)=1

lo g_{2} (x - 1) + lo g_{2} (x) = 1

Frequently Asked Questions (FAQ)

What is the answer to ln(2^x)+ln(e^x)=3 ?
The answer to ln(2^x)+ln(e^x)=3 is x= 3/(ln(2e))