What is the answer to log_{2}(x-1)+log_{2}(x)=1 ?

The answer to log_{2}(x-1)+log_{2}(x)=1 is x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x-1)+log_{2}(x)=1

lo g_{2} (x - 1) + lo g_{2} (x) = 1

x = 2

Solution steps

lo g_{2} (x - 1) + lo g_{2} (x) = 1

Apply log rules

(x - 1) x = 2

Solve

(x - 1) x = 2 : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions:

x = 2

True

, x = - 1

False

The solution is

x = 2

lo g_{4} (x) + lo g_{4} (x^{2}) = 5

lo g_{2} (y) = 3

ln (x + 3) + ln (x + 7) = ln (77)

0.5 = lo g_{10} (x)

ln (x) = e^{2}

What is the answer to log_{2}(x-1)+log_{2}(x)=1 ?
The answer to log_{2}(x-1)+log_{2}(x)=1 is x=2
Solve for x: log_{2}(x-1)+log_{2}(x)=1
The solution is x=2