What is the answer to ln(x)-ln(x+1)=1 ?

The answer to ln(x)-ln(x+1)=1 is No Solution for x\in\mathbb{R}

Solve for x: ln(x)-ln(x+1)=1

The solution is No Solution for x\in\mathbb{R}

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ln (x) - ln (x + 1) = 1

No Solution for x \in R

Solution steps

ln (x) - ln (x + 1) = 1

Add

ln (x + 1)

to both sides

ln (x) - ln (x + 1) + ln (x + 1) = 1 + ln (x + 1)

Simplify

ln (x) = 1 + ln (x + 1)

Apply log rules

x = e (x + 1)

Solve

x = e (x + 1) : x = \frac{e}{1 - e}

x = \frac{e}{1 - e}

Verify Solutions:

x = \frac{e}{1 - e}

False

The solution is

No Solution for x \in R

0.64 = lo g_{10} (x)

y^{3 l o g_{10} (y)} = 100 y

lo g_{x} (27) = \frac{3}{4}

lo g_{3} (2 x - 6) = 2

lo g_{10} (- x - 4) + lo g_{10} (3) = 1

What is the answer to ln(x)-ln(x+1)=1 ?
The answer to ln(x)-ln(x+1)=1 is No Solution for x\in\mathbb{R}
Solve for x: ln(x)-ln(x+1)=1
The solution is No Solution for x\in\mathbb{R}