What is the answer to log_{10}(-x-4)+log_{10}(3)=1 ?

The answer to log_{10}(-x-4)+log_{10}(3)=1 is x=-22/3

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log_{10}(-x-4)+log_{10}(3)=1

lo g_{10} (- x - 4) + lo g_{10} (3) = 1

x = - \frac{22}{3}

Solution steps

lo g_{10} (- x - 4) + lo g_{10} (3) = 1

Move

lo g_{10} (3)

to the right side

lo g_{10} (- x - 4) = 1 - lo g_{10} (3)

Apply log rules

- x - 4 = \frac{10}{3}

Solve

- x - 4 = \frac{10}{3} : x = - \frac{22}{3}

x = - \frac{22}{3}

Verify Solutions:

x = - \frac{22}{3}

True

The solution is

x = - \frac{22}{3}

lo g_{2} (x + 7) + lo g_{2} (x + 5) = 3

ln (x) + ln (x + 2) = ln (8)

2 lo g_{4} (2 - x) - lo g_{4} (x + 5) = 1

lo g_{4} (x) = 4

lo g_{10} (3 x + 4) = 3

What is the answer to log_{10}(-x-4)+log_{10}(3)=1 ?
The answer to log_{10}(-x-4)+log_{10}(3)=1 is x=-22/3
Solve for x: log_{10}(-x-4)+log_{10}(3)=1
The solution is x=-22/3