What is the answer to ln(7-4x)=-10 ?

The answer to ln(7-4x)=-10 is x=(-1+7e^{10})/(4e^{10)}

Solve for x: ln(7-4x)=-10

The solution is x=(-1+7e^{10})/(4e^{10)}

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ln (7 - 4 x) = - 10

x = \frac{- 1 + 7 e ^{10}}{4 e ^{10}}

Decimal Notation

x = 1.74998 \dots

Solution steps

ln (7 - 4 x) = - 10

Apply log rules

7 - 4 x = \frac{1}{e ^{10}}

Solve

7 - 4 x = \frac{1}{e ^{10}} : x = \frac{- 1 + 7 e ^{10}}{4 e ^{10}}

x = \frac{- 1 + 7 e ^{10}}{4 e ^{10}}

x, z = ln (x^{2} + y^{2})

lo g_{10} (x^{2} + 3 x) = 1

lo g_{32} (x) = \frac{1}{5}

0.345 = ln (x^{2})

lo g_{10} (x) + lo g_{10} (x + 1) = 1

What is the answer to ln(7-4x)=-10 ?
The answer to ln(7-4x)=-10 is x=(-1+7e^{10})/(4e^{10)}
Solve for x: ln(7-4x)=-10
The solution is x=(-1+7e^{10})/(4e^{10)}