What is the answer to log_{10}(x^2+3x)=1 ?

The answer to log_{10}(x^2+3x)=1 is x=2,x=-5

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log_{10}(x^2+3x)=1

lo g_{10} (x^{2} + 3 x) = 1

x = 2, x = - 5

Solution steps

lo g_{10} (x^{2} + 3 x) = 1

Apply log rules

x^{2} + 3 x = 10

Solve

x^{2} + 3 x = 10 : x = 2, x = - 5

x = 2, x = - 5

lo g_{32} (x) = \frac{1}{5}

0.345 = ln (x^{2})

lo g_{10} (x) + lo g_{10} (x + 1) = 1

lo g_{7} (x + 1) + lo g_{7} (x - 5) = 1

2 lo g_{9} (5 x) = 3

What is the answer to log_{10}(x^2+3x)=1 ?
The answer to log_{10}(x^2+3x)=1 is x=2,x=-5
Solve for x: log_{10}(x^2+3x)=1
The solution is x=2,x=-5