What is the answer to log_{7}(x+1)+log_{7}(x-5)=1 ?

The answer to log_{7}(x+1)+log_{7}(x-5)=1 is x=6

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log_{7}(x+1)+log_{7}(x-5)=1

lo g_{7} (x + 1) + lo g_{7} (x - 5) = 1

x = 6

Solution steps

lo g_{7} (x + 1) + lo g_{7} (x - 5) = 1

Apply log rules

(x + 1) (x - 5) = 7

Solve

(x + 1) (x - 5) = 7 : x = 6, x = - 2

x = 6, x = - 2

Verify Solutions:

x = 6

True

, x = - 2

False

The solution is

x = 6

2 lo g_{9} (5 x) = 3

ln (3 x + 1) = 2

lo g_{10} (5 x) = lo g_{10} (2 x + 9)

ln ((x - 1)^{2} (x - 2)^{2}) = ln (4)

lo g_{5} (12 x + 5) = 3

What is the answer to log_{7}(x+1)+log_{7}(x-5)=1 ?
The answer to log_{7}(x+1)+log_{7}(x-5)=1 is x=6
Solve for x: log_{7}(x+1)+log_{7}(x-5)=1
The solution is x=6