What is the answer to ln((x-1)^2(x-2)^2)=ln(4) ?

The answer to ln((x-1)^2(x-2)^2)=ln(4) is x=0,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln((x-1)^2(x-2)^2)=ln(4)

ln ((x - 1)^{2} (x - 2)^{2}) = ln (4)

x = 0, x = 3

Solution steps

ln ((x - 1)^{2} (x - 2)^{2}) = ln (4)

Apply log rules

(x - 1)^{2} (x - 2)^{2} = 4

Solve

(x - 1)^{2} (x - 2)^{2} = 4 : x = 0, x = 3

x = 0, x = 3

Verify Solutions:

x = 0

True

, x = 3

True

The solutions are

x = 0, x = 3

lo g_{5} (12 x + 5) = 3

lo g_{3} (p) + lo g_{27} (3 p) = - 1

4 ln (5 x + 3) - 11 = 13

lo g_{6} (4 (x - 1)) = 2

2 lo g_{10} (x) = 2

What is the answer to ln((x-1)^2(x-2)^2)=ln(4) ?
The answer to ln((x-1)^2(x-2)^2)=ln(4) is x=0,x=3
Solve for x: ln((x-1)^2(x-2)^2)=ln(4)
The solution is x=0,x=3