What is the answer to ln(2x+1)+ln(x+1)=0 ?

The answer to ln(2x+1)+ln(x+1)=0 is x=0

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ln(2x+1)+ln(x+1)=0

ln (2 x + 1) + ln (x + 1) = 0

x = 0

Solution steps

ln (2 x + 1) + ln (x + 1) = 0

Apply log rules

(2 x + 1) (x + 1) = 1

Solve

(2 x + 1) (x + 1) = 1 : x = 0, x = - \frac{3}{2}

x = 0, x = - \frac{3}{2}

Verify Solutions:

x = 0

True

, x = - \frac{3}{2}

False

The solution is

x = 0

2.5 = - lo g_{10} (x)

2 = lo g_{2} (x)

ln (4 - x) + ln (2) = 2 ln (x)

0.8 = lo g_{10} (x)

lo g_{10} (b) 50 = 1

What is the answer to ln(2x+1)+ln(x+1)=0 ?
The answer to ln(2x+1)+ln(x+1)=0 is x=0
Solve for x: ln(2x+1)+ln(x+1)=0
The solution is x=0