What is the answer to ln(4-x)+ln(2)=2ln(x) ?

The answer to ln(4-x)+ln(2)=2ln(x) is x=2

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ln(4-x)+ln(2)=2ln(x)

ln (4 - x) + ln (2) = 2 ln (x)

x = 2

Solution steps

ln (4 - x) + ln (2) = 2 ln (x)

Apply log rules

(4 - x) \cdot 2 = x^{2}

Solve

(4 - x) \cdot 2 = x^{2} : x = 2, x = - 4

x = 2, x = - 4

Verify Solutions:

x = 2

True

, x = - 4

False

The solution is

x = 2

0.8 = lo g_{10} (x)

lo g_{10} (b) 50 = 1

ln (7 x + 1) = 2 ln (x + 3) - ln (2)

lo g_{4} (2^{3 - 5 x}) = x^{2}

lo g_{10} (x + 8) + lo g_{10} (9) = 1

What is the answer to ln(4-x)+ln(2)=2ln(x) ?
The answer to ln(4-x)+ln(2)=2ln(x) is x=2
Solve for x: ln(4-x)+ln(2)=2ln(x)
The solution is x=2