What is the answer to log_{7}(6-2t)=2 ?

The answer to log_{7}(6-2t)=2 is t=-43/2

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log_{7}(6-2t)=2

lo g_{7} (6 - 2 t) = 2

t = - \frac{43}{2}

Solution steps

lo g_{7} (6 - 2 t) = 2

Apply log rules

6 - 2 t = 49

Solve

6 - 2 t = 49 : t = - \frac{43}{2}

t = - \frac{43}{2}

ln (ln (x)) = 3

lo g_{2} (\frac{3 x + 1}{4 x - 3}) = 3

lo g_{x} (6) = \frac{1}{2}

lo g_{2} (2 x + 5) = 3

ln (x) + ln (7 x + 1) = 1

What is the answer to log_{7}(6-2t)=2 ?
The answer to log_{7}(6-2t)=2 is t=-43/2
Solve for t: log_{7}(6-2t)=2
The solution is t=-43/2