What is the answer to ln(x)+ln(7x+1)=1 ?

The answer to ln(x)+ln(7x+1)=1 is x=(-1+sqrt(1+28e))/(14)

Solve for x: ln(x)+ln(7x+1)=1

The solution is x=(-1+sqrt(1+28e))/(14)

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ln (x) + ln (7 x + 1) = 1

x = \frac{- 1 + 1 + 28 e}{14}

Solution steps

ln (x) + ln (7 x + 1) = 1

Apply log rules

x (7 x + 1) = e

Solve

x (7 x + 1) = e : x = \frac{- 1 + 1 + 28 e}{14}, x = \frac{- 1 - 1 + 28 e}{14}

x = \frac{- 1 + 1 + 28 e}{14}, x = \frac{- 1 - 1 + 28 e}{14}

Verify Solutions:

x = \frac{- 1 + 1 + 28 e}{14}

True

, x = \frac{- 1 - 1 + 28 e}{14}

False

The solution is

x = \frac{- 1 + 1 + 28 e}{14}

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lo g_{2} (x - 5) = 2 - lo g_{2} (x - 8)

ln (x^{2}) - 0.7 = 0

0.69 = lo g_{10} (x)

3 ln (2 x) - 4 = 2 ln (2 x)

What is the answer to ln(x)+ln(7x+1)=1 ?
The answer to ln(x)+ln(7x+1)=1 is x=(-1+sqrt(1+28e))/(14)
Solve for x: ln(x)+ln(7x+1)=1
The solution is x=(-1+sqrt(1+28e))/(14)