What is the answer to log_{x}(4)+log_{x}(64)=2 ?

The answer to log_{x}(4)+log_{x}(64)=2 is x=16

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log_{x}(4)+log_{x}(64)=2

lo g_{x} (4) + lo g_{x} (64) = 2

x = 16

Solution steps

lo g_{x} (4) + lo g_{x} (64) = 2

Apply log rules

\frac{ln ( 4 \cdot 64 )}{ln ( x )} = 2

Multiply both sides by

ln (x)

\frac{ln ( 4 \cdot 64 )}{ln ( x )} ln (x) = 2 ln (x)

Apply log rules

x = 16

Verify Solutions:

x = 16

True

The solution is

x = 16

ln (9 x + e) = 1

ln (x + 1) = lo g_{2} (3)

lo g_{2} (x + 2) - lo g_{2} (x - 1) = 1

6 ln (4 x - 10) - 2 = 40

ln (x) + ln (x - 2) = 4

What is the answer to log_{x}(4)+log_{x}(64)=2 ?
The answer to log_{x}(4)+log_{x}(64)=2 is x=16
Solve for x: log_{x}(4)+log_{x}(64)=2
The solution is x=16