What is the answer to log_{3}(x-4)+log_{3}(x+4)=2 ?

The answer to log_{3}(x-4)+log_{3}(x+4)=2 is x=5

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log_{3}(x-4)+log_{3}(x+4)=2

lo g_{3} (x - 4) + lo g_{3} (x + 4) = 2

x = 5

Solution steps

lo g_{3} (x - 4) + lo g_{3} (x + 4) = 2

Apply log rules

(x - 4) (x + 4) = 9

Solve

(x - 4) (x + 4) = 9 : x = 5, x = - 5

x = 5, x = - 5

Verify Solutions:

x = 5

True

, x = - 5

False

The solution is

x = 5

lo g_{\frac{1}{2}} (x) = - 2

lo g_{10} (2 x) + lo g_{10} (x) = 11

lo g_{4} (- 2 x + 11) = 2

lo g_{3} (x) + lo g_{9} (x) = 12

x, z = ln (4 - x - y)

What is the answer to log_{3}(x-4)+log_{3}(x+4)=2 ?
The answer to log_{3}(x-4)+log_{3}(x+4)=2 is x=5
Solve for x: log_{3}(x-4)+log_{3}(x+4)=2
The solution is x=5