What is the answer to log_{3}(-2x+4)=2 ?

The answer to log_{3}(-2x+4)=2 is x=-5/2

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log_{3}(-2x+4)=2

lo g_{3} (- 2 x + 4) = 2

x = - \frac{5}{2}

Decimal Notation

x = - 2.5

Solution steps

lo g_{3} (- 2 x + 4) = 2

Apply log rules

- 2 x + 4 = 9

Solve

- 2 x + 4 = 9 : x = - \frac{5}{2}

x = - \frac{5}{2}

ln (x) + ln (x - 9) = 0

\frac{ln ( x ) - 1}{ln ^{2} ( x )} = 0

- lo g_{10} (x) = 3

ln (x^{2} - 4 x + 5) = 0

lo g_{3} (4 x) - lo g_{3} (8) = 3

What is the answer to log_{3}(-2x+4)=2 ?
The answer to log_{3}(-2x+4)=2 is x=-5/2
Solve for x: log_{3}(-2x+4)=2
The solution is x=-5/2