What is the answer to ln(2x-3)-ln(x+1)=e ?

The answer to ln(2x-3)-ln(x+1)=e is No Solution for x\in\mathbb{R}

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ln(2x-3)-ln(x+1)=e

ln (2 x - 3) - ln (x + 1) = e

No Solution for x \in R

Solution steps

ln (2 x - 3) - ln (x + 1) = e

Add

ln (x + 1)

to both sides

ln (2 x - 3) - ln (x + 1) + ln (x + 1) = e + ln (x + 1)

Simplify

ln (2 x - 3) = e + ln (x + 1)

Apply log rules

2 x - 3 = e^{e} (x + 1)

Solve

2 x - 3 = e^{e} (x + 1) : x = \frac{e ^{e} + 3}{2 - e ^{e}}

x = \frac{e ^{e} + 3}{2 - e ^{e}}

Verify Solutions:

x = \frac{e ^{e} + 3}{2 - e ^{e}}

False

The solution is

No Solution for x \in R

lo g_{10} ((x + 2)^{2}) = 2

lo g_{8} (3 x + 1) + 16 = 18

lo g_{1 - x} (\frac{3}{2}) = 0.5

0.36 = lo g_{10} (x)

0.52 = lo g_{10} (x)

What is the answer to ln(2x-3)-ln(x+1)=e ?
The answer to ln(2x-3)-ln(x+1)=e is No Solution for x\in\mathbb{R}