What is the answer to 4log_{3}(x-40)=16 ?

The answer to 4log_{3}(x-40)=16 is x=121

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4log_{3}(x-40)=16

4 lo g_{3} (x - 40) = 16

x = 121

Solution steps

4 lo g_{3} (x - 40) = 16

Divide both sides by

4

lo g_{3} (x - 40) = 4

Apply log rules

x - 40 = 81

Solve

x - 40 = 81 : x = 121

x = 121

Verify Solutions:

x = 121

True

The solution is

x = 121

lo g_{2} (5 x - 8) = 1

lo g_{10} (x) + lo g_{10} (x) = 2

lo g_{3} (x - 2) + lo g_{3} (2 x - 7) = 2

lo g_{3} ((r + 3)^{2}) = 4

- x + 2 = ln (x)

What is the answer to 4log_{3}(x-40)=16 ?
The answer to 4log_{3}(x-40)=16 is x=121
Solve for x: 4log_{3}(x-40)=16
The solution is x=121