What is the answer to log_{3}((r+3)^2)=4 ?

The answer to log_{3}((r+3)^2)=4 is r=6,r=-12

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log_{3}((r+3)^2)=4

lo g_{3} ((r + 3)^{2}) = 4

r = 6, r = - 12

Solution steps

lo g_{3} ((r + 3)^{2}) = 4

Apply log rules

(r + 3)^{2} = 81

Solve

(r + 3)^{2} = 81 : r = 6, r = - 12

r = 6, r = - 12

- x + 2 = ln (x)

ln (x) + ln (x - 3) = ln (4)

ln (4 x + 1) - ln (3) = 5

lo g_{2} (1 - y) - lo g_{2} (5 + y) = 3

lo g_{x} (3) = 2

What is the answer to log_{3}((r+3)^2)=4 ?
The answer to log_{3}((r+3)^2)=4 is r=6,r=-12
Solve for r: log_{3}((r+3)^2)=4
The solution is r=6,r=-12