What is the answer to ln(2x+1)+ln(x-3)-2ln(x)=0 ?

The answer to ln(2x+1)+ln(x-3)-2ln(x)=0 is x=(5+sqrt(37))/2

Solve for x: ln(2x+1)+ln(x-3)-2ln(x)=0

The solution is x=(5+sqrt(37))/2

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ln (2 x + 1) + ln (x - 3) - 2 ln (x) = 0

x = \frac{5 + 37}{2}

Decimal Notation

x = 5.54138 \dots

Solution steps

ln (2 x + 1) + ln (x - 3) - 2 ln (x) = 0

Apply log rules

(2 x + 1) (x - 3) = x^{2}

Solve

(2 x + 1) (x - 3) = x^{2} : x = \frac{5 + 37}{2}, x = \frac{5 - 37}{2}

x = \frac{5 + 37}{2}, x = \frac{5 - 37}{2}

Verify Solutions:

x = \frac{5 + 37}{2}

True

, x = \frac{5 - 37}{2}

False

The solution is

x = \frac{5 + 37}{2}

lo g_{2} (4 x + 6) = 1

lo g_{6} (x - 2) + lo g_{6} (x + 3) = 2

lo g_{10} (n) = 1000000

lo g_{10} (x + 2) - (x - 1) = 1

0.49 = lo g_{10} (x)

What is the answer to ln(2x+1)+ln(x-3)-2ln(x)=0 ?
The answer to ln(2x+1)+ln(x-3)-2ln(x)=0 is x=(5+sqrt(37))/2
Solve for x: ln(2x+1)+ln(x-3)-2ln(x)=0
The solution is x=(5+sqrt(37))/2