What is the answer to log_{6}(x)+log_{6}(x-5)=1 ?

The answer to log_{6}(x)+log_{6}(x-5)=1 is x=6

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log_{6}(x)+log_{6}(x-5)=1

lo g_{6} (x) + lo g_{6} (x - 5) = 1

x = 6

Solution steps

lo g_{6} (x) + lo g_{6} (x - 5) = 1

Apply log rules

x (x - 5) = 6

Solve

x (x - 5) = 6 : x = 6, x = - 1

x = 6, x = - 1

Verify Solutions:

x = 6

True

, x = - 1

False

The solution is

x = 6

lo g_{3} (x) = ln (x)

lo g_{3} (x - 2) + lo g_{3} (x + 4) = 3

3 + 2 lo g_{2} (x) = lo g_{2} (14 x - 3)

lo g_{2} (5 x - 3) = 5

0.53 = lo g_{10} (x)

What is the answer to log_{6}(x)+log_{6}(x-5)=1 ?
The answer to log_{6}(x)+log_{6}(x-5)=1 is x=6
Solve for x: log_{6}(x)+log_{6}(x-5)=1
The solution is x=6