What are the solutions to the equation x^2+11x+2=0 ?

The solutions to the equation x^2+11x+2=0 are x=(-11+sqrt(113))/2 ,x=(-11-sqrt(113))/2

Find the zeros of x^2+11x+2=0

The zeros of x^2+11x+2=0 are x=(-11+sqrt(113))/2 ,x=(-11-sqrt(113))/2

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x^{2} + 11 x + 2 = 0

x = \frac{- 11 + 113}{2}, x = \frac{- 11 - 113}{2}

Decimal Notation

x = - 0.18492 \dots, x = - 10.81507 \dots

Solution steps

x^{2} + 11 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 2 = 113

x_{1, 2} = \frac{- 11 \pm 113}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 113}{2 \cdot 1}, x_{2} = \frac{- 11 - 113}{2 \cdot 1}

x = \frac{- 11 + 113}{2 \cdot 1} : \frac{- 11 + 113}{2}

x = \frac{- 11 - 113}{2 \cdot 1} : \frac{- 11 - 113}{2}

The solutions to the quadratic equation are:

x = \frac{- 11 + 113}{2}, x = \frac{- 11 - 113}{2}

x^{- \frac{5}{3}}

\frac{5}{12} (x + 2) = \frac{2}{3} (2 x + 1) + \frac{1}{6}

\frac{81 x ^{2} y ^{3}}{9 x y ^{2}}

(x - 5)^{2} + 5 = 49

∣ 4 - 3 x ∣ = 4

What are the solutions to the equation x^2+11x+2=0 ?
The solutions to the equation x^2+11x+2=0 are x=(-11+sqrt(113))/2 ,x=(-11-sqrt(113))/2
Find the zeros of x^2+11x+2=0
The zeros of x^2+11x+2=0 are x=(-11+sqrt(113))/2 ,x=(-11-sqrt(113))/2