What is the answer to ln(3-2x)=-4 ?

The answer to ln(3-2x)=-4 is x=(-1+3e^4)/(2e^4)

Solve for x: ln(3-2x)=-4

The solution is x=(-1+3e^4)/(2e^4)

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ln (3 - 2 x) = - 4

x = \frac{- 1 + 3 e ^{4}}{2 e ^{4}}

Decimal Notation

x = 1.49084 \dots

Solution steps

ln (3 - 2 x) = - 4

Apply log rules

3 - 2 x = \frac{1}{e ^{4}}

Solve

3 - 2 x = \frac{1}{e ^{4}} : x = \frac{- 1 + 3 e ^{4}}{2 e ^{4}}

x = \frac{- 1 + 3 e ^{4}}{2 e ^{4}}

0.72 = lo g_{10} (x)

lo g_{x} (\frac{8}{125}) = - 3

lo g_{x} (2 x^{x - 2} - 1) + 4 = 2 x

lo g_{10} (x - 3) = 1 - lo g_{10} (x)

- 1 + ln (x - 3) = 0

What is the answer to ln(3-2x)=-4 ?
The answer to ln(3-2x)=-4 is x=(-1+3e^4)/(2e^4)
Solve for x: ln(3-2x)=-4
The solution is x=(-1+3e^4)/(2e^4)