What is the answer to log_{4}(x)+log_{2}(x)=6 ?

The answer to log_{4}(x)+log_{2}(x)=6 is x=16

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log_{4}(x)+log_{2}(x)=6

lo g_{4} (x) + lo g_{2} (x) = 6

x = 16

Solution steps

lo g_{4} (x) + lo g_{2} (x) = 6

Apply log rules

x = 16

Verify Solutions:

x = 16

True

The solution is

x = 16

lo g_{2} (3 x - 4) = 5

lo g_{x} (64) = \frac{3}{2}

0.82 = lo g_{10} (x)

lo g_{3} (- 2 x - 3) = 2

lo g_{b} (8) = \frac{3}{2}

What is the answer to log_{4}(x)+log_{2}(x)=6 ?
The answer to log_{4}(x)+log_{2}(x)=6 is x=16
Solve for x: log_{4}(x)+log_{2}(x)=6
The solution is x=16