What is the answer to log_{5}(-2x+10)=2 ?

The answer to log_{5}(-2x+10)=2 is x=-15/2

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log_{5}(-2x+10)=2

lo g_{5} (- 2 x + 10) = 2

x = - \frac{15}{2}

Decimal Notation

x = - 7.5

Solution steps

lo g_{5} (- 2 x + 10) = 2

Apply log rules

- 2 x + 10 = 25

Solve

- 2 x + 10 = 25 : x = - \frac{15}{2}

x = - \frac{15}{2}

- 4 lo g_{3} (- 9 m) = - 4

lo g_{2} (x) = lo g_{x} (2)

16 lo g_{r} (4) = lo g_{4} (r)

lo g_{3} (x^{2} - 3 x + 1) = 0

lo g_{10} (x) = 0.61

What is the answer to log_{5}(-2x+10)=2 ?
The answer to log_{5}(-2x+10)=2 is x=-15/2
Solve for x: log_{5}(-2x+10)=2
The solution is x=-15/2