What is the answer to 2log_{2}(x+5)-log_{2}(x+9)=1 ?

The answer to 2log_{2}(x+5)-log_{2}(x+9)=1 is x=-1

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2log_{2}(x+5)-log_{2}(x+9)=1

2 lo g_{2} (x + 5) - lo g_{2} (x + 9) = 1

x = - 1

Solution steps

2 lo g_{2} (x + 5) - lo g_{2} (x + 9) = 1

Apply log rules

(x + 5)^{2} = 2 (x + 9)

Solve

(x + 5)^{2} = 2 (x + 9) : x = - 1, x = - 7

x = - 1, x = - 7

Verify Solutions:

x = - 1

True

, x = - 7

False

The solution is

x = - 1

x, ln (y) = 2 ln (x)

ln (x) + ln (x + 1) = ln (12)

lo g_{3} (x) = - \frac{2}{3}

lo g_{5} (x) + 2 = lo g_{5} (7)

lo g_{x} (\frac{1}{81}) = 2

What is the answer to 2log_{2}(x+5)-log_{2}(x+9)=1 ?
The answer to 2log_{2}(x+5)-log_{2}(x+9)=1 is x=-1
Solve for x: 2log_{2}(x+5)-log_{2}(x+9)=1
The solution is x=-1