What is the answer to log_{5}(x-2)+log_{5}(x+2)=1 ?

The answer to log_{5}(x-2)+log_{5}(x+2)=1 is x=3

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log_{5}(x-2)+log_{5}(x+2)=1

lo g_{5} (x - 2) + lo g_{5} (x + 2) = 1

x = 3

Solution steps

lo g_{5} (x - 2) + lo g_{5} (x + 2) = 1

Apply log rules

(x - 2) (x + 2) = 5

Solve

(x - 2) (x + 2) = 5 : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions:

x = 3

True

, x = - 3

False

The solution is

x = 3

lo g_{6} (x + 1) + lo g_{6} (2) = 1

1 + 2 lo g_{4} (t + 1) = 2 lo g_{2} (t)

lo g_{5} (3 x - 2) = 1 + lo g_{5} (x - 4)

ln (x + 5) = 2

lo g_{8} (x^{3}) - lo g_{x} (8) = 2

What is the answer to log_{5}(x-2)+log_{5}(x+2)=1 ?
The answer to log_{5}(x-2)+log_{5}(x+2)=1 is x=3
Solve for x: log_{5}(x-2)+log_{5}(x+2)=1
The solution is x=3