What is the answer to log_{3}(2x)=log_{9}(6x-2) ?

The answer to log_{3}(2x)=log_{9}(6x-2) is x=1,x= 1/2

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log_{3}(2x)=log_{9}(6x-2)

lo g_{3} (2 x) = lo g_{9} (6 x - 2)

x = 1, x = \frac{1}{2}

Decimal Notation

x = 1, x = 0.5

Solution steps

lo g_{3} (2 x) = lo g_{9} (6 x - 2)

Apply log rules

4 x^{2} = 6 x - 2

Solve

4 x^{2} = 6 x - 2 : x = 1, x = \frac{1}{2}

x = 1, x = \frac{1}{2}

Verify Solutions:

x = 1

True

, x = \frac{1}{2}

True

The solutions are

x = 1, x = \frac{1}{2}

ln (x - 5) = 7

5 lo g_{4} (4 x) = 15

2 ln (- 2 x) = 0

lo g_{2} (y) = 5

ln (2 x - 1) = 3

What is the answer to log_{3}(2x)=log_{9}(6x-2) ?
The answer to log_{3}(2x)=log_{9}(6x-2) is x=1,x= 1/2
Solve for x: log_{3}(2x)=log_{9}(6x-2)
The solution is x=1,x= 1/2