What is the answer to ln(x)-ln(x+1)=4 ?

The answer to ln(x)-ln(x+1)=4 is No Solution for x\in\mathbb{R}

Solve for x: ln(x)-ln(x+1)=4

The solution is No Solution for x\in\mathbb{R}

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ln (x) - ln (x + 1) = 4

No Solution for x \in R

Solution steps

ln (x) - ln (x + 1) = 4

Add

ln (x + 1)

to both sides

ln (x) - ln (x + 1) + ln (x + 1) = 4 + ln (x + 1)

Simplify

ln (x) = 4 + ln (x + 1)

Apply log rules

x = e^{4} (x + 1)

Solve

x = e^{4} (x + 1) : x = \frac{e ^{4}}{1 - e ^{4}}

x = \frac{e ^{4}}{1 - e ^{4}}

Verify Solutions:

x = \frac{e ^{4}}{1 - e ^{4}}

False

The solution is

No Solution for x \in R

4 = lo g_{10} (x)

lo g_{4} (2 x + 1) - lo g_{4} (x - 2) = 1

y, 3 ln (t) - ln (y) = 4

ln (12) - ln (x - 1) = ln (x - 2)

11.5 = - lo g_{10} (x)

What is the answer to ln(x)-ln(x+1)=4 ?
The answer to ln(x)-ln(x+1)=4 is No Solution for x\in\mathbb{R}
Solve for x: ln(x)-ln(x+1)=4
The solution is No Solution for x\in\mathbb{R}