What is the answer to 2ln(x+1)-ln(4x)=0 ?

The answer to 2ln(x+1)-ln(4x)=0 is x=1

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2ln(x+1)-ln(4x)=0

2 ln (x + 1) - ln (4 x) = 0

x = 1

Solution steps

2 ln (x + 1) - ln (4 x) = 0

Apply log rules

(x + 1)^{2} = 4 x

Solve

(x + 1)^{2} = 4 x : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

lo g_{10} (5) + lo g_{10} (3 x - 2) = 1

lo g_{3} (4 x^{2}) - lo g_{3} (2) = 5

lo g_{10} (x) = 2.5

lo g_{x} (7) = 3

5 ln (4 x - 10) + 11 = 1

What is the answer to 2ln(x+1)-ln(4x)=0 ?
The answer to 2ln(x+1)-ln(4x)=0 is x=1
Solve for x: 2ln(x+1)-ln(4x)=0
The solution is x=1